Prove rightarrow sin (90^{o}-theta)cos (90^{o}-theta)=dfrac {tan  theta}{1+tan ^{2}theta}

Prove rightarrow sin (90^{o}-theta)cos (90^{o}-theta)=dfrac {tan theta}{1+tan ^{2}theta}

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Click here👆to get an answer to your question ✍️ Prove rightarrow sin -90-o-theta-cos -90-o-theta-dfrac -tan theta-1-tan -2-theta-
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सिद्ध कीजिए कि sin(90^(@)-theta)cos(90^(@)-theta)=(tan theta)/(1+cot^(2 )(90^(@)-theta)), 10

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