Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. Draw line BC = 11 cm. Make an angle of 30° at B and 90° at C using a protractor. Bisect angles B and C, and these bisectors will meet at one-point X. Now draw perpendicular bisectors on BX and CX, which will cut the line segment BC on point Y and Z respectively. Now join XY and XZ to get the required triangle XYZ.
It is given that we have to construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ + ZX = 11 cm. We have drawn the triangle using a compass and ruler and justified the construction.

XYZ is a right angle triangle with angleX = 90°, XY=9cm,and YZ=12cm. OX is perpendicular to YZ. What is OX? - Quora

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ

Construct a triangle XYZ in which ∠Y=30∘, ∠Z=90∘ and XY+YZ+ZX=11 cm.[4 marks][NCERT][Construction of Triangles : Given Perimeter and Two Base Angles]

e xyz in which Ly -30) lange ABC 1 which BC 8 cm. z in which yz 28 cm 0:17 Construct an angle of 30, 60, 45,2 Q:18 construct a triangle xyz

cbse-ncert-9th-class-Chapter-12-Constructions

Question 1 - Construct XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6

Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + YZ

constructions

NCERT Solutions Class 9 Maths Chapter 1 – Constructions I Free PDF Download

NCERT Solutions for Class 9 Math Constructions

Class 9 NCERT Solutions- Chapter 11 Constructions - Exercise 11.2 - GeeksforGeeks