A particle starts from rest. Its acceleration (a) versus time (t) is as shown in the figure. The maximum speed of the particle will be:660 m/s55m/s110m/s550 m/s
Click here:point_up_2:to get an answer to your question :writing_hand:a particle starts from rest its acceleration a versus time t is as shown in 2
Click here👆to get an answer to your question ✍️ A particle starts from rest- Its acceleration -a- versus time -t- is as shown in the figure- The maximum speed of the particle will be-660 m-s55m-s110m-s550 m-s
Given-u-0m-s Particle initially at restAcceleration- a-dvdtdv-adtv-x222B-adt- - - - - - - - -1-From the above equation- velocity of the particle is equal to the area under the acceleration-time curve-From the given acceleration-time graph-vmax-12-xD7-base-xD7-heightvmax-12-xD7-11-xD7-10vmax-55m-sThe correct option is B
A particle starts from rest. Its acceleration (a) versus time (t
SOLVED: particle starts from rest and accelerates as shown in the
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A particle starts from rest and moves with a constant acceleration
A particle starts from rest and accelerates as shown in the figure
1. A particle starts from rest. Its acceleration (a) versus time
A particle starts from rest. Its acceleration 1) versus time(t) is
A particle starting from rest. Its acceleration (a) versus time (t) is
42. If a particle starts from rest, its acceleration (@) versus
SOLVED: A particle starts from rest and accelerates as shown in
A particle starts from rest. Its acceleration at time t=0 is 5 m//s^(2
A particle starts from rest. Its acceleration (a) versus time (t) is as
A particle starts from rest. Its acceleration time graph is as
